4g^2+20g=25

Solution for 4g^2+20g=25 equation:

4g^2+20g=25

We move all terms to the left:

4g^2+20g-(25)=0

a = 4; b = 20; c = -25;
Δ = b2-4ac
Δ = 202-4·4·(-25)
Δ = 800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{800}=\sqrt{400*2}=\sqrt{400}*\sqrt{2}=20\sqrt{2}$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20\sqrt{2}}{2*4}=\frac{-20-20\sqrt{2}}{8}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20\sqrt{2}}{2*4}=\frac{-20+20\sqrt{2}}{8}
$